The figure shows a relation R between the sets P and Q. The relation R in Set-builder form is

Question

The figure shows a relation R between the sets P and Q. <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/mathematics/d9afd480d85745784309da72f8940e6a-.png" /> The relation R in Set-builder form is (A)  (x, y): x ∈ P, y ∈ Q  (B)  (x, y): x ∈ Q, y ∈ P  (C)  (x, y): x is the square of y, x ∈ P, y ∈ Q  (D)  (x, y): y is the square of x, x ∈ P, y ∈ Q

Tardigrade Admin · Accepted Answer

It is obvious that the relation R is ' x is the square of y '. In Set-builder form, R= (x, y): x is the square of y, x ∈ P, y ∈ Q

Q. The figure shows a relation $R$ between the sets $P$ and $Q$ .

The relation $R$ in Set-builder form is

${(x, y) : x \in P, y \in Q}$

${(x, y) : x \in Q, y \in P}$

${(x, y) : x$ is the square of $y, x \in P, y \in Q}$

${(x, y) : y$ is the square of $x, x \in P, y \in Q}$

It is obvious that the relation $R$ is ' $x$ is the square of $y$ '. In Set-builder form, $R = {(x, y) : x$ is the square of $y, x \in P, y \in Q}$

Q. The figure shows a relation R between the sets P and Q. The relation R in Set-builder form is

{(x,y):x∈P,y∈Q}

{(x,y):x∈Q,y∈P}

{(x,y):x is the square of y,x∈P,y∈Q}

{(x,y):y is the square of x,x∈P,y∈Q}