The figure shows a potentiometer arrangement used to measure the internal resistance of the cell B. The null point Q is located at 20 cm from point P on a 100 cm wire PR. Find the internal resistance of the cell B.

Question

The figure shows a potentiometer arrangement used to measure the internal resistance of the cell B. The null point Q is located at 20 cm from point P on a 100 cm wire PR. Find the internal resistance of the cell B. <img class="img-fluid question-image" alt="Question" src="https://cdn.tardigrade.in/q/nta/p-4kvwq1fznyq34adm.jpg" /> (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

(5 R/20 + R)+5=4 (5 R/20 + R)=1 20+R=5R 4R=20 R=5

Q. The figure shows a potentiometer arrangement used to measure the internal resistance of the cell B. The null point $Q$ is located at $20 c m$ from point $P$ on a $100 c m$ wire PR. Find the internal resistance of the cell $B .$

$\frac{5 R}{20 + R} + 5 = 4$
$\frac{5 R}{20 + R} = 1$
$20 + R = 5 R$
$4 R = 20$
$R = 5$

Q. The figure shows a potentiometer arrangement used to measure the internal resistance of the cell B. The null point Q is located at 20cm from point P on a 100cm wire PR. Find the internal resistance of the cell B.

20+R5R​+5=4 20+R5R​=1 20+R=5R 4R=20 R=5

Q. The figure shows a potentiometer arrangement used to measure the internal resistance of the cell B. The null point $Q$ is located at $20 c m$ from point $P$ on a $100 c m$ wire PR. Find the internal resistance of the cell $B .$

$\frac{5 R}{20 + R} + 5 = 4$
$\frac{5 R}{20 + R} = 1$
$20 + R = 5 R$
$4 R = 20$
$R = 5$