The figure gives the electric potential V as a function of distance through four regions on x-axis. Which of the following is true for the magnitude of the electric field E in these regions?

Question

The figure gives the electric potential V as a function of distance through four regions on x-axis. Which of the following is true for the magnitude of the electric field E in these regions? (A) EB =ED and EA< EC (B) EA > EB > EC > ED (C) EA < EB < EC < ED (D) EA = EC and EB < ED

Tardigrade Admin · Accepted Answer

In region A, V = constant ⇒ EA=0 In region B, EB=(4-2/2)=1 vm-1 In region C, V = constant Ec=0 In Region D, ED=(4-2/1)=2 vm-1 Here EA=Ec and Ec and EB < ED

Q. The figure gives the electric potential V as a function of distance through four regions on x-axis. Which of the following is true for the magnitude of the electric field E in these regions?

E_B =E_D and E_A< E_C

E_A > E_B > E_C > E_D

E_A < E_B < E_C < E_D

E_A = E_C and E_B < E_D

In region A, V = constant $\Rightarrow E_{A} = 0$
In region B, $E_{B} = \frac{4 - 2}{2} = 1 v m^{- 1}$
In region C, V = constant $E_{c} = 0$
In Region D, $E_{D} = \frac{4 - 2}{1} = 2 v m^{- 1}$
$Here E_{A} = E_{c} an d E_{c} an d E_{B} < E_{D}$

Q. The figure gives the electric potential V as a function of distance through four regions on x-axis. Which of the following is true for the magnitude of the electric field E in these regions?

EB =ED and EA< EC

EA > EB > EC > ED

EA < EB < EC < ED

EA = EC and EB < ED

In region A, V = constant ⇒EA​=0 In region B, EB​=24−2​=1vm−1 In region C, V = constant Ec​=0 In Region D, ED​=14−2​=2vm−1 HereEA​=Ec​andEc​andEB​<ED​

E_B =E_D and E_A< E_C

E_A > E_B > E_C > E_D

E_A < E_B < E_C < E_D

E_A = E_C and E_B < E_D

In region A, V = constant $\Rightarrow E_{A} = 0$
In region B, $E_{B} = \frac{4 - 2}{2} = 1 v m^{- 1}$
In region C, V = constant $E_{c} = 0$
In Region D, $E_{D} = \frac{4 - 2}{1} = 2 v m^{- 1}$
$Here E_{A} = E_{c} an d E_{c} an d E_{B} < E_{D}$