Tardigrade
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Tardigrade
Question
Physics
The figure below shows currents in a part of electric circuit. The current i is
Q. The figure below shows currents in a part of electric circuit. The current
i
is
3989
213
Current Electricity
Report Error
A
1.7 A
B
3.7 A
C
1.3 A
D
1 A
Solution:
According to Kirchhoff's first law
At junction
A
,
i
A
B
=
2
+
2
=
4
A
At junction
B
,
i
A
B
=
i
BC
−
1
=
3
A
At junction
C
,
i
=
i
BC
−
1.3
=
3
−
1.3
=
1.7
A