The eye can be regarded as a single refracting surface . The radius of curvature of this surface is equal to that of cornea (7.8 mm ). This surface separates two media of refractive indices 1 and 1.34. Calculate the distance from the refracting surface at which a parallel beam of light will come to focus.

Question

The eye can be regarded as a single refracting surface . The radius of curvature of this surface is equal to that of cornea (7.8 mm ). This surface separates two media of refractive indices 1 and 1.34. Calculate the distance from the refracting surface at which a parallel beam of light will come to focus. (A) 2 cm (B) 1 cm (C) 3.1 cm (D) 4.0 cm

Tardigrade Admin · Accepted Answer

(1.34/V) - (1/∞) = (1.34-1/7.8) ∴ V= 30.7 mm

$2 c m$

$1 c m$

$3.1 c m$

$4.0 c m$

$\frac{1.34}{V} - \frac{1}{\infty} = \frac{1.34 - 1}{7.8}$
$∴ V = 30.7 mm$

2cm

1cm

3.1cm

4.0cm

V1.34​−∞1​=7.81.34−1​ ∴V=30.7mm

$2 c m$

$1 c m$

$3.1 c m$

$4.0 c m$

$\frac{1.34}{V} - \frac{1}{\infty} = \frac{1.34 - 1}{7.8}$
$∴ V = 30.7 mm$