The external and internal radius of a hollow cylinder are measured to be (4.23 ± 0.01) cm and (3.89 ± 0.01) cm, respectively. The thickness of the wall of the cylinder is

Question

The external and internal radius of a hollow cylinder are measured to be (4.23 ± 0.01) cm and (3.89 ± 0.01) cm, respectively. The thickness of the wall of the cylinder is (A) (0.34 ± 0.02) cm (B) (0.17 ± 0.02) cm (C) (0.17 ± 0.01) cm (D) (0.34 ± 0.01) cm

Tardigrade Admin · Accepted Answer

Thickness of wall (t) = r, - r2 t = 4.23 - 3.89 = 0.34 cm Δ t = ± (Δ r1 + Δ r2) = (0.01 + 0.01) = 0.02 cm ∴ Thickness of wall =( t ± Δ t) = (0.34 ± 0.02) cm

Q. The external and internal radius of a hollow cylinder are measured to be $(4.23 \pm 0.01) c m$ and $(3.89 \pm 0.01) c m$ , respectively. The thickness of the wall of the cylinder is

$(0.34 \pm 0.02) c m$

$(0.17 \pm 0.02) c m$

$(0.17 \pm 0.01) c m$

$(0.34 \pm 0.01) c m$

Thickness of wall $(t) = r, - r_{2}$
$t = 4.23 - 3.89 = 0.34 c m$
$Δ t = \pm (Δ r_{1} + Δ r_{2}) = (0.01 + 0.01) = 0.02 c m$
$∴$ Thickness of wall $= (t \pm Δ t) = (0.34 \pm 0.02) c m$

Q. The external and internal radius of a hollow cylinder are measured to be (4.23±0.01)cm and (3.89±0.01)cm, respectively. The thickness of the wall of the cylinder is

(0.34±0.02)cm

(0.17±0.02)cm

(0.17±0.01)cm

(0.34±0.01)cm