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Tardigrade
Question
Mathematics
The expression sin -1((1/√2))+ sec -1(-√2)+ tan -1(-1)+ operatornamecosec-1(-√2)+ cos -1(-(1/2))+ tan -1(1-√2)+ cot -1(√2+1) simplifies to
Q. The expression
sin
−
1
(
2
1
)
+
sec
−
1
(
−
2
)
+
tan
−
1
(
−
1
)
+
cosec
−
1
(
−
2
)
+
cos
−
1
(
−
2
1
)
+
tan
−
1
(
1
−
2
)
+
cot
−
1
(
2
+
1
)
simplifies to
676
132
Inverse Trigonometric Functions
Report Error
A
π
B
6
7
π
C
0
D
2
π
Solution:
4
π
+
4
3
π
−
4
π
−
4
π
+
3
2
π
−
8
π
+
8
π
=
6
7
π