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Tardigrade
Question
Mathematics
The expression (cos 6x+6 cos 4x + 15 cos 2x + 10/cos 5x + 5 cos 3x +10 cos x) is equal to
Q. The expression
cos
5
x
+
5
cos
3
x
+
10
cos
x
cos
6
x
+
6
cos
4
x
+
15
cos
2
x
+
10
is equal to
1850
186
Trigonometric Functions
Report Error
A
cos
2
x
23%
B
2
cos
x
40%
C
co
s
2
x
20%
D
1
+
cos
x
.
17%
Solution:
The given expression can be written as
cos
5
x
+
5
cos
3
x
+
10
cos
x
(
cos
6
x
+
cos
4
x
)
+
5
(
cos
4
x
+
cos
2
x
)
+
10
(
cos
2
x
+
1
)
=
cos
5
x
+
5
cos
3
x
+
10
cos
x
2
cos
5
x
cos
x
+
5.2
cos
3
x
cos
x
+
10.2
co
s
2
x
=
cos
5
x
+
5
cos
3
x
+
10
cos
x
2
cos
x
(
cos
5
x
+
5
cos
3
x
+
10
cos
x
)
=
2
cos
x