Question

The experimental data for the reaction,$2A+B_2\to 2AB,$ is

Expt. No	$\left[A\right]$	$\left[B_2\right]$	$Rate\left(s^{-1}\right)$
1.	$0.50$	$0.50$	$1.6\times 10^{-4}$
2.	$0.50$	$1.00$	$3.2\times 10^{-4}$
3.	$1.0$	$1.00$	$3.2\times 10^{-4}$

The rate equation for the above data is -

• A. $rate=k{\left[B_2\right]}^2$
• B. $rate=k\left[B\right]$
• C. $rate=k{\left[A\right]}^2{\left[B\right]}^2$
• D. $rate=k{\left[A\right]}^2\left[B\right]$

Answer 1

Answer: (B)

$r=k{\left[A\right]}^x{\left[B\right]}^y$
$1.6\times 10^{-4}=k{\left[0.5\right]}^x{\left[0.5\right]}^y.....\left(1\right)$
$3.2\times 10^{-4}=k{\left[0.5\right]}^x{\left[1.0\right]}^y.....\left(2\right)$
$3.2\times 10^{-4}=k{\left[1.0\right]}^x{\left[1.0\right]}^y.....\left(3\right)$
$\left(2\right)÷\left(1\right)2=2y\Rightarrow y=1$
$\left(3\right)÷\left(2\right)1=2x\Rightarrow x=0$
$r=k{\left[A\right]}^{\circ }{\left[B\right]}^1\Rightarrow r=K\left[B\right]$