The excess pressure inside the first soap bubble is three times that inside the second bubble. Then the ratio of the volumes of the first and second bubbles is:

Question

The excess pressure inside the first soap bubble is three times that inside the second bubble. Then the ratio of the volumes of the first and second bubbles is: (A) 1:3 (B) 1:9 (C) 1:27 (D) 3:1

Tardigrade Admin · Accepted Answer

(r1/r2)=(p2/p1)=(1/3);(V1/ V2)=(r13/r23)=(1/27)

Q. The excess pressure inside the first soap bubble is three times that inside the second bubble. Then the ratio of the volumes of the first and second bubbles is:

$1 : 3$

$1 : 9$

$1 : 27$

$3 : 1$

$\frac{r _{1}}{r _{2}} = \frac{p _{2}}{p _{1}} = \frac{1}{3}; \frac{V _{1}}{V _{2}} = \frac{r _{1}^{3}}{r _{2}^{3}} = \frac{1}{27}$