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Q. The excess pressure inside the first soap bubble is three times that inside the second bubble. Then the ratio of the volumes of the first and second bubbles is:

NTA AbhyasNTA Abhyas 2020

Solution:

$\frac{r_{1}}{r_{2}}=\frac{p_{2}}{p_{1}}=\frac{1}{3};\frac{V_{1}}{ V_{2}}=\frac{r_{1}^{3}}{r_{2}^{3}}=\frac{1}{27}$