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Physics
The excess pressure inside the first soap bubble is three times that inside the second bubble. Then the ratio of the volumes of the first and second bubbles is:
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Q. The excess pressure inside the first soap bubble is three times that inside the second bubble. Then the ratio of the volumes of the first and second bubbles is:
NTA Abhyas
NTA Abhyas 2020
A
$1:3$
B
$1:9$
C
$1:27$
D
$3:1$
Solution:
$\frac{r_{1}}{r_{2}}=\frac{p_{2}}{p_{1}}=\frac{1}{3};\frac{V_{1}}{ V_{2}}=\frac{r_{1}^{3}}{r_{2}^{3}}=\frac{1}{27}$