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Question
Chemistry
The equivalent weight of potassium permanganate (KMnO4) in neutral medium will be equal to
Q. The equivalent weight of potassium permanganate
(
K
M
n
O
4
)
in neutral medium will be equal to
1534
177
BHU
BHU 2009
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A
molecular weight
B
2
molecular weight
C
3
molecular weight
D
5
molecular weight
Solution:
Equivalent weight of
K
M
n
O
4
in neutral medium is as:
2
K
M
n
O
4
+
7
+
H
2
O
→
2
K
O
H
+
2
M
n
O
2
+
4
+
3
[
O
]
∴
Equivalent weight
=
3
molecular weight