The equivalent weight of phosphoric acid ( H 3 PO 4) in the reaction: NaOH + H 3 PO 4 arrow NaH 2 PO 4+ H 2 O is

Question

The equivalent weight of phosphoric acid ( H 3 PO 4) in the reaction: NaOH + H 3 PO 4 arrow NaH 2 PO 4+ H 2 O is (A) 25 (B) 49 (C) 59 (D) 98

Tardigrade Admin · Accepted Answer

The given reaction is: NaOH + H 3 PO 4 arrow NaH 2 PO 4+ H 2 O Molecular mass of H 3 PO 4 is 98 . As there is only one electron change involved therefore, equivalent weight of H 3 PO 4 in this reaction is, (98/1)=98

Q. The equivalent weight of phosphoric acid $(H_{3} P O_{4})$ in the reaction:
$N a O H + H_{3} P O_{4} \to N a H_{2} P O_{4} + H_{2} O$ is

25

49

59

98

The given reaction is :

$N a O H + H_{3} P O_{4} \to N a H_{2} P O_{4} + H_{2} O$

Molecular mass of $H_{3} P O_{4}$ is $98.$

As there is only one electron change involved therefore, equivalent weight of $H_{3} P O_{4}$ in this reaction is, $\frac{98}{1} = 98$

Q. The equivalent weight of phosphoric acid (H3​PO4​) in the reaction: NaOH+H3​PO4​→NaH2​PO4​+H2​O is

25

49

59

98

The given reaction is : NaOH+H3​PO4​→NaH2​PO4​+H2​O Molecular mass of H3​PO4​ is 98. As there is only one electron change involved therefore, equivalent weight of H3​PO4​ in this reaction is, 198​=98

Q. The equivalent weight of phosphoric acid $(H_{3} P O_{4})$ in the reaction:
$N a O H + H_{3} P O_{4} \to N a H_{2} P O_{4} + H_{2} O$ is

The given reaction is :

$N a O H + H_{3} P O_{4} \to N a H_{2} P O_{4} + H_{2} O$

Molecular mass of $H_{3} P O_{4}$ is $98.$

As there is only one electron change involved therefore, equivalent weight of $H_{3} P O_{4}$ in this reaction is, $\frac{98}{1} = 98$