The equivalent weight of textN texta text2 textS text2 textO text3 in the following reaction is 2Na2S2O3+I2 xrightarrowNa2S4O6+2NaI

Question

The equivalent weight of textN texta text2 textS text2 textO text3 in the following reaction is 2Na2S2O3+I2 xrightarrowNa2S4O6+2NaI  (A) M (B) M/8 (C) M/0.5 (D) M/2

Tardigrade Admin · Accepted Answer

2S2O32- xrightarrowS4O62-+2e- ENa2S2O3=(2M/2)=M

Q. The equivalent weight of $N a_{2} S_{2} O_{3}$ in the following reaction is $2 N a_{2} S_{2} O_{3} + I_{2} N a_{2} S_{4} O_{6} + 2 N a I$

M

M/8

M/0.5

M/2

$2 S_{2} O_{3}^{2 -} S_{4} O_{6}^{2 -} + 2 e^{-}$ $E_{N a_{2} S_{2} O_{3}} = \frac{2 M}{2} = M$

Q. The equivalent weight of Na2​S2​O3​ in the following reaction is 2Na2​S2​O3​+I2​​Na2​S4​O6​+2NaI

M

M/8

M/0.5

M/2

2S2​O32−​​S4​O62−​+2e− ENa2​S2​O3​​=22M​=M

Q. The equivalent weight of $N a_{2} S_{2} O_{3}$ in the following reaction is $2 N a_{2} S_{2} O_{3} + I_{2} N a_{2} S_{4} O_{6} + 2 N a I$

$2 S_{2} O_{3}^{2 -} S_{4} O_{6}^{2 -} + 2 e^{-}$ $E_{N a_{2} S_{2} O_{3}} = \frac{2 M}{2} = M$