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  4. The equivalent weight of textN texta text2 textS text2 textO text3 in the following reaction is 2Na2S2O3+I2 xrightarrowNa2S4O6+2NaI

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Q. The equivalent weight of $ \text{N}{{\text{a}}_{\text{2}}}{{\text{S}}_{\text{2}}}{{\text{O}}_{\text{3}}} $ in the following reaction is $ 2N{{a}_{2}}{{S}_{2}}{{O}_{3}}+{{I}_{2}}\xrightarrow{{}}N{{a}_{2}}{{S}_{4}}{{O}_{6}}+2NaI $

Jharkhand CECEJharkhand CECE 2014

Solution:

$ 2{{S}_{2}}O_{3}^{2-}\xrightarrow{{}}{{S}_{4}}O_{6}^{2-}+2{{e}^{-}} $ $ {{E}_{N{{a}_{2}}{{S}_{2}}{{O}_{3}}}}=\frac{2M}{2}=M $