The equivalent weight of MnSO4 is half its molecular weight when it is converted to:

Question

The equivalent weight of MnSO4 is half its molecular weight when it is converted to: (A) Mn2 O3 (B) MnO2 (C) MnO-4 (D) MnO2-4

Tardigrade Admin · Accepted Answer

Equivalent weight =(molecular weight/valency factor) If valency factor is 2, then equivalent weight will be equal to its molecular weight. In MnSO4, the oxidation state of Mn is +II In Mn2O3, the oxidation state of Mn is +III In MnO2, the oxidation state of Mn is +IV In MnO-4, the oxidation state of Mn is +VII In MnO2-4; the oxidation state of Mn is +VI Thus, when MnSO4 is converted into MnO2, then the valency factor is 2, and the equivalent weight of MnSO4 will be half of its molecular weight.

Q. The equivalent weight of $M n S O_{4}$ is half its molecular weight when it is converted to:

$M n_{2} O_{3}$

$M n O_{2}$

$M n O_{4}^{-}$

$M n O_{4}^{2 -}$

Q. The equivalent weight of MnSO4​ is half its molecular weight when it is converted to:

Mn2​O3​

MnO2​

MnO4−​

MnO42−​

Q. The equivalent weight of $M n S O_{4}$ is half its molecular weight when it is converted to:

$M n_{2} O_{3}$

$M n O_{2}$

$M n O_{4}^{-}$

$M n O_{4}^{2 -}$