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Question
Chemistry
The equivalent weight of KMnO4 (formula weight = M) when it is used as an oxidant in neutral medium is
Q. The equivalent weight of
K
M
n
O
4
(formula weight
=
M
)
when it is used as an oxidant in neutral medium is
1812
238
The d-and f-Block Elements
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A
M
30%
B
2
M
30%
C
3
M
28%
D
5
M
12%
Solution:
In neutral medium,
2
K
M
n
O
4
+
H
2
O
→
2
K
O
H
+
2
M
n
O
2
+
3
[
O
]
or
M
n
O
4
−
+
2
H
2
O
+
3
e
−
→
M
n
O
2
+
4
O
H
−
∴
Eq. weight of
K
M
n
O
4
=
3
Mol.wt