1. Tardigrade
  2. Question
  3. Chemistry
  4. The equivalent weight of KMnO4 (formula weight = M) when it is used as an oxidant in neutral medium is

Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. The equivalent weight of $KMnO_4$ (formula weight $= M)$ when it is used as an oxidant in neutral medium is

The d-and f-Block Elements

Solution:

In neutral medium,
$2KMnO_4 + H_2O \rightarrow 2KOH + 2MnO_2 + 3[O]$
or $MnO_4^- + 2H_2O + 3e^- \rightarrow MnO_2 + 4OH^-$
$\therefore $ Eq. weight of $KMnO_4 = \frac{\text{Mol.wt}}{3}$