The equivalent weight of K 4[ Fe ( CN )6] in the given reaction is: K 4[ Fe ( CN )6] xrightarrow [O] Fe 3++ NO 3-+ CO 2

Question

The equivalent weight of K 4[ Fe ( CN )6] in the given reaction is: K 4[ Fe ( CN )6] xrightarrow [O] Fe 3++ NO 3-+ CO 2 (A) M / 20 (B) M / 1 (C) M / 60 (D) M / 61

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/chemistry/c4292f0e79199a7c60720cf9d2eac0ec-.png" /> Net change in oxidation number =+60+1=+61 Eq. wt. =(M/61)

Q. The equivalent weight of $K_{4} [F e (CN)_{6}]$ in the given reaction is:
$K_{4} [F e (CN)_{6}] [O] F e^{3 +} + N O_{3}^{-} + C O_{2}$

M / 20

M / 1

M / 60

M / 61

Net change in oxidation number $= + 60 + 1 = + 61$

Eq. wt. $= \frac{M}{61}$

Q. The equivalent weight of K4​[Fe(CN)6​] in the given reaction is: K4​[Fe(CN)6​][O]​Fe3++NO3−​+CO2​