The equivalent weight of an element is 4 . Its chloride has a vapour density 59.25 Then the valency of the element is

Question

The equivalent weight of an element is 4 . Its chloride has a vapour density 59.25 Then the valency of the element is (A) 4 (B) 3 (C) 2 (D) 1

Tardigrade Admin · Accepted Answer

Molecular weight of chloride =59.25 × 2=118.5 Let the valency of metal is x then chloride is M Cl x ∴ Molecular weight of chloride = Equivalent weight of metal × x+x × 35.5 118.5=4 x+35.5 x ⇒ x=(118.5/39.5)=3

Q. The equivalent weight of an element is $4.$ Its chloride has a vapour density $59.25$ Then the valency of the element is

4

3

2

1

Molecular weight of chloride $= 59.25 \times 2 = 118.5$

Let the valency of metal is $x$ then chloride is $MC l_{x}$

$∴$ Molecular weight of chloride = Equivalent weight of metal $\times x + x \times 35.5$

$118.5 = 4 x + 35.5 x$

$\Rightarrow x = \frac{118.5}{39.5} = 3$

Q. The equivalent weight of an element is 4. Its chloride has a vapour density 59.25 Then the valency of the element is

4

3

2

1

Molecular weight of chloride =59.25×2=118.5 Let the valency of metal is x then chloride is MClx​ ∴ Molecular weight of chloride = Equivalent weight of metal ×x+x×35.5 118.5=4x+35.5x ⇒x=39.5118.5​=3

Q. The equivalent weight of an element is $4.$ Its chloride has a vapour density $59.25$ Then the valency of the element is

Molecular weight of chloride $= 59.25 \times 2 = 118.5$

Let the valency of metal is $x$ then chloride is $MC l_{x}$

$∴$ Molecular weight of chloride = Equivalent weight of metal $\times x + x \times 35.5$

$118.5 = 4 x + 35.5 x$

$\Rightarrow x = \frac{118.5}{39.5} = 3$