The equivalent weight of a solid element is found to be 9. If the specific heat of this element is 1.05 Jg-1K-1, then its atomic weight is:

Question

The equivalent weight of a solid element is found to be 9. If the specific heat of this element is 1.05 Jg-1K-1, then its atomic weight is: (A) 17 (B) 21 (C) 25 (D) 27

Tardigrade Admin · Accepted Answer

By using: Valency of an element =( text Approximate weight / text Equivalent weight ) =(26.8 / text specific heat / text Equivalent weight ) =(26.8 / 1.05/9)=2.835 ≅ 3 Now, by using Atomic weight = Equivalent weight × valency = 9 × 3 = 27

Q. The equivalent weight of a solid element is found to be $9$ . If the specific heat of this element is $1.05 J g^{- 1} K^{- 1},$ then its atomic weight is:

17

21

25

27

By using :
Valency of an element
$= \frac{Approximate weight}{Equivalent weight}$
$= \frac{26.8/ specific heat}{Equivalent weight}$
$= \frac{26.8/1.05}{9} = 2.835 ≅ 3$
Now, by using
Atomic weight = Equivalent weight $\times$ valency
$= 9 \times 3 = 27$

Q. The equivalent weight of a solid element is found to be 9. If the specific heat of this element is 1.05Jg−1K−1, then its atomic weight is:

17

21

25

27

By using : Valency of an element = Equivalent weight Approximate weight ​ = Equivalent weight 26.8/ specific heat ​ =926.8/1.05​=2.835≅3 Now, by using Atomic weight = Equivalent weight × valency =9×3=27

Q. The equivalent weight of a solid element is found to be $9$ . If the specific heat of this element is $1.05 J g^{- 1} K^{- 1},$ then its atomic weight is:

By using :
Valency of an element
$= \frac{Approximate weight}{Equivalent weight}$
$= \frac{26.8/ specific heat}{Equivalent weight}$
$= \frac{26.8/1.05}{9} = 2.835 ≅ 3$
Now, by using
Atomic weight = Equivalent weight $\times$ valency
$= 9 \times 3 = 27$