Question

The equivalent weight of a solid element is found to be $9$. If the specific heat of this element is $1.05J{g}^{-1}{K}^{-1}$, then its atomic weight is

• A. 17
• B. 21
• C. 25
• D. 27

Answer 1

Answer: (D)

Atomic weight
$=$ Equivalent weight $\times$ valency .
Here equivalent weight $=9$
Specific heat of element $=1.05J{g}^{-1}{K}^{-1}$
By using
Valency of element $=\frac{\text{ approximate weight }}{\text{ equivalent weight }}$
$=\frac{26.8}{\text{ specific heat }}$
$=\frac{26.8/1.05}{9}$
$=2.835\approx 3$
$\because$ Atomic weight $=$ equivalent weight $\times$ valency
$=9\times 3=27$