Question

The equivalent circuit is
The circuit represents

• A. NAND gate
• B. OR gate
• C. AND gate
• D. NOR gate

Answer 1

Answer: (D)

Output of $NOR$ gate
$y^{\prime }=\overline{A+B}$
Output of NAND gate
$y^{\prime \prime }=\overline{(A+B)\cdot (A+B)}$
$=\overline{(A+B)(A+B)}$
$=(A+B)(A+B)$
$A+B$
Output of $NOT$ gate
$y^{\prime \prime \prime \prime }=\overline{A+B}$
$\therefore$ The Boolean expression is for NOR gate.