Question

The equivalent capacitance of the combination of the capacitors is

• A. $3.20\mu F$
• B. $7.80\mu F$
• C. $3.90\mu F$
• D. $2.16\mu F$

Answer 1

Answer: (A)

Equivalent capacitance of two parallel capacitors $10\mu F$ and $6\mu F=\left(10+6\right)\mu F=16\mu F$ This $16\mu F$ capacitor is in series combination with $4\mu F$ capacitor,
$\therefore$ Equivalent capacitance of the entire combination $=\frac{16\times 4}{16+4}=\frac{64}{20}=3.2\mu F$