The equilibrium P4(s)+6 C l2(g) leftharpoons 4 P C l3(g) is attained by mixing equal moles of P 4 and Cl 2 in an evacuated vessel. Then, at equilibrium

Question

The equilibrium P4(s)+6 C l2(g) leftharpoons 4 P C l3(g) is attained by mixing equal moles of P 4 and Cl 2 in an evacuated vessel. Then, at equilibrium (A) [ Cl 2]>[ PCl 3] (B) [ Cl 2]>[ P 4] (C) [P4]>[C l2] (D) [ PCl 3]>[ P 4]

Tardigrade Admin · Accepted Answer

For the reaction: P4(s)+6 Cl 2(g) 4 PCl 3(g) <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/chemistry/620683de6bec7412ce4ff52eeb0fee8f-.png" /> Hence, at equilibrium? [P4]>[ Cl 2]

Q. The equilibrium $P_{4} (s) + 6 C l_{2} (g) ⇌ 4 PC l_{3} (g)$ is attained by mixing equal moles of $P_{4}$ and $C l_{2}$ in an evacuated vessel. Then, at equilibrium

$[C l_{2}] > [PC l_{3}]$

$[C l_{2}] > [P_{4}]$

$[P_{4}] > [C l_{2}]$

$[PC l_{3}] > [P_{4}]$

For the reaction: $P_{4} (s) + 6 C l_{2} (g) 4 PC l_{3} (g)$

Hence, at equilibrium? $[P_{4}] > [C l_{2}]$

Q. The equilibrium P4​(s)+6Cl2​(g)⇌4PCl3​(g) is attained by mixing equal moles of P4​ and Cl2​ in an evacuated vessel. Then, at equilibrium

[Cl2​]>[PCl3​]

[Cl2​]>[P4​]

[P4​]>[Cl2​]

[PCl3​]>[P4​]