The equilibrium constant Kc value for a gaseous homogeneous equilibrium at 227°C is 2.05 × 10-5 mol L-1 . The Kp value in atmosphere for this equilibrium at this same temperature is (R=8.2 × 10-2 L atm K-1 mol-1)

Question

The equilibrium constant Kc value for a gaseous homogeneous equilibrium at 227°C is 2.05 × 10-5 mol L-1 . The Kp value in atmosphere for this equilibrium at this same temperature is (R=8.2 × 10-2 L atm K-1 mol-1)  (A)  5.0 × 10-6  (B)  8.405 × 10-4  (C)  5.0 × 10-5  (D)  8.405 × 10-3

Tardigrade Admin · Accepted Answer

Kp=Kc(RT)Δ n From the units of Kc, Δ n=1 ⇒ Kp=2.05× 10-5 (8.2× 10-2× 500) =8.405× 10-4

Q. The equilibrium constant $K_{c}$ value for a gaseous homogeneous equilibrium at $22 7^{\circ} C$ is $2.05 \times 1 0^{- 5} m o l L^{- 1}$ . The $K_{p}$ value in atmosphere for this equilibrium at this same temperature is
$(R = 8.2 \times 1 0^{- 2} L a t m K^{- 1} m o l^{- 1})$

$5.0 \times 1 0^{- 6}$

$8.405 \times 1 0^{- 4}$

$5.0 \times 1 0^{- 5}$

$8.405 \times 1 0^{- 3}$

$K_{p} = K_{c} (RT)^{Δ n}$
From the units of $K_{c}, Δ n = 1$
$\Rightarrow K_{p} = 2.05 \times 1 0^{- 5} (8.2 \times 1 0^{- 2} \times 500)$
$= 8.405 \times 1 0^{- 4}$

Q. The equilibrium constant Kc​ value for a gaseous homogeneous equilibrium at 227∘C is 2.05×10−5molL−1 . The Kp​ value in atmosphere for this equilibrium at this same temperature is (R=8.2×10−2LatmK−1mol−1)

5.0×10−6

8.405×10−4

5.0×10−5

8.405×10−3