Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Chemistry
The equilibrium constant (Kc) for the reaction N2(g) + O2 (g) → 2NO (g) at temperature T is 4 Ã 10-4. Thevalue of Kc for the reaction NO(g) → (1/2) N2(g) + (1/2) O2(g) at the same temperature is :
Q. The equilibrium constant
(
K
c
)
for the reaction
N
2
(
g
)
+
O
2
(
g
)
→
2
NO
(
g
)
at temperature T is
4
×
1
0
−
4
. Thevalue of Kc for the reaction
NO
(
g
)
→
2
1
N
2
(
g
)
+
2
1
O
2
(
g
)
at the same temperature is :
4563
218
AIEEE
AIEEE 2012
Equilibrium
Report Error
A
0.02
100%
B
2.5
×
1
0
2
0%
C
4
×
1
0
−
4
0%
D
50.0
0%
Solution:
N
2
+
O
2
→
2
NO
K
=
4
×
1
0
−
4
NO
→
2
1
N
2
+
2
1
O
2
K
′
=
K
1
=
4
×
1
0
−
4
1
=
50