The equilibrium constant (Kc) for the reaction HA + B leftharpoons BH+ + A- is 100. If the rate constant for the forward reaction is 105, then rate constant for the backward reaction is

Question

The equilibrium constant (Kc) for the reaction HA + B leftharpoons BH+ + A- is 100. If the rate constant for the forward reaction is 105, then rate constant for the backward reaction is (A) 107 (B) 103 (C) 10-3 (D) 10-5

Tardigrade Admin · Accepted Answer

Kc=(Kf/Kb)∴ Kb =(Kf/Kc)=(105/100) =103

Q. The equilibrium constant $(K_{c})$ for the reaction $H A + B ⇌ B H^{+} + A^{-}$ is $100$ . If the rate constant for the forward reaction is $1 0^{5}$ , then rate constant for the backward reaction is

$1 0^{7}$

$1 0^{3}$

$1 0^{- 3}$

$1 0^{- 5}$

$K_{c} = \frac{K _{f}}{K _{b}} ∴ K_{b} = \frac{K _{f}}{K _{c}} = \frac{1 0 ^{5}}{100} = 1 0^{3}$

Q. The equilibrium constant (Kc​) for the reaction HA+B⇌BH++A− is 100. If the rate constant for the forward reaction is 105, then rate constant for the backward reaction is

107

103

10−3

10−5