1. Tardigrade
  2. Question
  3. Chemistry
  4. The equilibrium constant (Kc) for the reaction HA + B leftharpoons BH+ + A- is 100. If the rate constant for the forward reaction is 105, then rate constant for the backward reaction is

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Q. The equilibrium constant $(K_c)$ for the reaction $HA + B \rightleftharpoons BH^{+} + A^{-}$ is $100$. If the rate constant for the forward reaction is $10^5$, then rate constant for the backward reaction is

Equilibrium

Solution:

$K_{c}=\frac{K_{f}}{K_{b}}\therefore K_{b} =\frac{K_{f}}{K_{c}}=\frac{10^{5}}{100} =10^{3}$