The equilibrium constant K C for the following reaction will be K 2 CO 3( aq )+ BaSO 4( s ) leftharpoons BaCO 3( s )+ K 2 SO 4( aq )

Question

The equilibrium constant K C for the following reaction will be K 2 CO 3( aq )+ BaSO 4( s ) leftharpoons BaCO 3( s )+ K 2 SO 4( aq ) (A) ([ CO 32-]/[ SO 42-]) (B) ([ K 2 CO 3]/[ K 2 SO 4]) (C) ([ BaSO 4]/[ CO 32-]) (D) ([ SO 42-]/[ CO 32-])

Tardigrade Admin · Accepted Answer

For the reaction, K c =([ BaCO 3][ K 2 SO 4]/[ K 2 CO 3][ BaSO 4]) ∵[ BaCO 3( s )]=1 [ BaSO 4( s )]=1 ⇒ K c =([ K 2 SO 4]/[ K 2 CO 3]) ∴ Both K 2 SO 4 and K 2 SO 3 are strong electrolytes ∴ K c =([ SO 42-]/[ CO 32-])

Q. The equilibrium constant $K_{C}$ for the following reaction will be
$K_{2} C O_{3} (a q) + B a S O_{4} (s) ⇌ B a C O_{3} (s) + K_{2} S O_{4} (a q)$

$\frac{[ C O _{3}^{2 -} ]}{[ S O _{4}^{2 -} ]}$

$\frac{[ K _{2} C O _{3} ]}{[ K _{2} S O _{4} ]}$

$\frac{[ B a S O _{4} ]}{[ C O _{3}^{2 -} ]}$

$\frac{[ S O _{4}^{2 -} ]}{[ C O _{3}^{2 -} ]}$

Q. The equilibrium constant KC​ for the following reaction will be K2​CO3​(aq)+BaSO4​(s)⇌BaCO3​(s)+K2​SO4​(aq)

[SO42−​][CO32−​]​

[K2​SO4​][K2​CO3​]​

[CO32−​][BaSO4​]​

[CO32−​][SO42−​]​

For the reaction, Kc​=[K2​CO3​][BaSO4​][BaCO3​][K2​SO4​]​ ∵[BaCO3​(s)]=1 [BaSO4​(s)]=1 ⇒Kc​=[K2​CO3​][K2​SO4​]​ ∴ Both K2​SO4​ and K2​SO3​ are strong electrolytes ∴Kc​=[CO32−​][SO42−​]​

Q. The equilibrium constant $K_{C}$ for the following reaction will be
$K_{2} C O_{3} (a q) + B a S O_{4} (s) ⇌ B a C O_{3} (s) + K_{2} S O_{4} (a q)$

$\frac{[ C O _{3}^{2 -} ]}{[ S O _{4}^{2 -} ]}$

$\frac{[ K _{2} C O _{3} ]}{[ K _{2} S O _{4} ]}$

$\frac{[ B a S O _{4} ]}{[ C O _{3}^{2 -} ]}$

$\frac{[ S O _{4}^{2 -} ]}{[ C O _{3}^{2 -} ]}$