Question

The equilibrium constant for the reaction,
$aA+bB\rightleftharpoons cC+dD$ is $K$, then the equilibrium constant for the reaction,
$naA+nbB\rightleftharpoons ncC+ndD$ will be

• A. $K$
• B. $K^n$
• C. $\frac{1}{K^n}$
• D. $\frac{1}{K^{n-1}}$

Answer 1

Answer: (B)

$aA+bB\rightleftharpoons cC+dD$
Equilibrium constant, $K=\frac{{\left[C\right]}^c{\left[D\right]}^d}{{\left[A\right]}^a{\left[B\right]}^b}$
$naA+nbB\rightleftharpoons ncC+ndD$
Equilibrium constant, $K^{\prime }=\frac{{\left[C\right]}^{nc}{\left[D\right]}^{nd}}{{\left[A\right]}^{na}{\left[B\right]}^{nb}}$
$=\left(\frac{{\left[C\right]}^c{\left[D\right]}^d}{{\left[A\right]}^a{\left[B\right]}^b}\right)=K^n$