Question

The equilibrium constant for the reaction,
$aA +bB { \rightleftharpoons} cC+dD$ is $K$, then the equilibrium constant for the reaction,
$naA+nbB {\rightleftharpoons} ncC +ndD$ will be

• A. $K$
• B. $K^{n}$
• C. $\frac{1}{K^{n}}$
• D. $\frac{1}{K^{n-1}}$

Answer 1

Answer: (B)

$aA +bB \rightleftharpoons cC +dD$
Equilibrium constant, $K=\frac{\left[C\right]^{c}\left[D\right]^{d}}{\left[A\right]^{a}\left[B\right]^{b}}$
$naA +nbB\rightleftharpoons ncC +ndD$
Equilibrium constant, $K'=\frac{\left[C\right]^{nc}\left[D\right]^{nd}}{\left[A\right]^{na}\left[B\right]^{nb}}$
$=\left(\frac{\left[C\right]^{c}\left[D\right]^{d}}{\left[A\right]^{a}\left[B\right]^{b}}\right)=K^{n}$