Q. The equilibrium constant for the following reactions are and , respectively.


Then, the equilibrium constant for the reaction
is

 1319  227 KVPYKVPY 2012Equilibrium Report Error

Solution:

If the equation is multiplied by the equilibrium constant for the new equation is the square of , i.e. .
If we add two equation, then the equilibrium constant of new equations is the product of the equilibrium constant of those equations.
For the reactions,



To obtain (iii) we multiply Eq. (ii) by and then add Eq. (i) to it.
Thus, equilibrium constant for Eq. (iii),