Question

The equilibrium constant for a reaction is $10$. What will be the value of $\Delta G^{°}$ at $300K$ ?

• A. $-5.74kJ$
• B. $-574kJ$
• C. $+11.48kJ$
• D. $+5.74kJ$

Answer 1

Answer: (A)

$\Delta G=-2.303RTlogK$
$=-2.303\times 8.314\times 300log10$
$=-5744.1J$
$\Rightarrow -5.74kJ$