The equilibrium concentration of the species in the reaction A+B ≡ C+D are 3,5,10 and 15 mole L-1 respectively at 300 K the Δ G for the reaction is :

Question

The equilibrium concentration of the species in the reaction A+B ≡ C+D are 3,5,10 and 15 mole L-1 respectively at 300 K the Δ G for the reaction is : (A) 13.81 (B) -1381.8 (C) -138.18 (D) 1391.6

Tardigrade Admin · Accepted Answer

Δ G=-2.303 R T log K, Here R=2 cal, T=300 K =(10 × 15/3 × 5)=10 ∴ Δ G =-2.303 × 2 × 300 × log 10 =-2.303 × 2 × 300 × 1 =-1381.8 cals

Q. The equilibrium concentration of the species in the reaction $A + B \equiv C + D$ are $3, 5, 10$ and 15 mole $L^{- 1}$ respectively at $300 K$ the $Δ G$ for the reaction is :

13.81

-1381.8

-138.18

1391.6

$Δ G = - 2.303 RT lo g K,$
Here $R = 2 c a l$ ,
$T = 300$
$K = \frac{10 \times 15}{3 \times 5} = 10$
$∴ Δ G = - 2.303 \times 2 \times 300 \times lo g 10$
$= - 2.303 \times 2 \times 300 \times 1$
$= - 1381.8 c a l s$

Q. The equilibrium concentration of the species in the reaction A+B≡C+D are 3,5,10 and 15 mole L−1 respectively at 300K the ΔG for the reaction is :