2013
220
Complex Numbers and Quadratic Equations
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Solution:
Given equation is x(log3x)2−29(log3x)+5=33/2
let log3x=y ⇒x=3y ∴xy2−29y+5=33/2 ∴(y2−29y+5)log3x=23log33
(taking log on both sides on base 3)
or (y2−29y+5)y=23
or, 2y3−9y2+10y−3=0
or (y−1)(y−3)(2y−1)=0
or, y=1 or y=3 or y=21
Now, x=3y ⇒x=31.33.312 in which all three are real and one is irrational