Question

The equation, ${\pi }^x=-2x^2+6x-9$ has:

• A. no solution
• B. one solution
• C. two solutions
• D. infinite solutions

Answer 1

Answer: (A)

${\pi }^x=-2x^2+6x-9$
RHS $=-2x^2+6x-9$
$D=36-4(-9)(-2)=36-72<0$
$-36<0$
RHS is always negative for all values of $x$ but LHS is positive always so no solution