The equation of transverse wave in stretched string is y=5 sin 2 π((t/0.04)-(x/50)) where distances are in cm and time in second. The wavelength of wave is

Question

The equation of transverse wave in stretched string is y=5 sin 2 π((t/0.04)-(x/50)) where distances are in cm and time in second. The wavelength of wave is (A) 15 cm (B) 10 cm (C) 25 cm (D) 50 cm

Tardigrade Admin · Accepted Answer

Comparing with equation of wave y=A sin 2 π((t/T)-(x/λ)) ; λ=50 cm

Q. The equation of transverse wave in stretched string is

$y = 5 sin 2 π (\frac{t}{0.04} - \frac{x}{50})$

where distances are in $c m$ and time in second. The wavelength of wave is

15 cm

10 cm

25 cm

50 cm

Comparing with equation of wave
$y = A sin 2 π (\frac{t}{T} - \frac{x}{λ}); λ = 50 c m$

Q. The equation of transverse wave in stretched string is y=5sin2π(0.04t​−50x​) where distances are in cm and time in second. The wavelength of wave is