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  4. The equation of transverse wave in stretched string is y=5 sin 2 π((t/0.04)-(x/50)) where distances are in cm and time in second. The wavelength of wave is

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Q. The equation of transverse wave in stretched string is

$y=5 \sin 2 \pi\left(\frac{t}{0.04}-\frac{x}{50}\right)$

where distances are in $cm$ and time in second. The wavelength of wave is

Waves

Solution:

Comparing with equation of wave
$y=A \sin 2 \pi\left(\frac{t}{T}-\frac{x}{\lambda}\right) ; \lambda=50\, cm$