The equation of the tangents to the circle x2 + y2 - 6x + 4y = 12, which are parallel to the straight line 4x + 3y + 5 = 0, are

Question

The equation of the tangents to the circle x2 + y2 - 6x + 4y = 12, which are parallel to the straight line 4x + 3y + 5 = 0, are (A) 3x - 4y - 19 = 0, 3x - 4y + 31 = 0  (B) 4x + 3y - 19 = 0, Ax + 3y + 31 = 0  (C) 4x + 3y + 19 = 0, 4x + 3y - 31 = 0  (D) 3x - 4y + 19 = 0, 3x - 4y + 31 = 0.

Tardigrade Admin · Accepted Answer

Correct answer is (c) 4x + 3y + 19 = 0, 4x + 3y - 31 = 0

Q. The equation of the tangents to the circle $x^{2} + y^{2} - 6 x + 4 y = 12$ , which are parallel to the straight line $4 x + 3 y + 5 = 0,$ are

$3 x - 4 y - 19 = 0, 3 x - 4 y + 31 = 0$

$4 x + 3 y - 19 = 0, A x + 3 y + 31 = 0$

$4 x + 3 y + 19 = 0, 4 x + 3 y - 31 = 0$

$3 x - 4 y + 19 = 0, 3 x - 4 y + 31 = 0.$

Correct answer is (c) $4 x + 3 y + 19 = 0, 4 x + 3 y - 31 = 0$

Q. The equation of the tangents to the circle x2+y2−6x+4y=12, which are parallel to the straight line 4x+3y+5=0, are

3x−4y−19=0,3x−4y+31=0

4x+3y−19=0,Ax+3y+31=0

4x+3y+19=0,4x+3y−31=0

3x−4y+19=0,3x−4y+31=0.