The equation of the radical axis of the two circles represented by the equations |z-2|=3 and |z-2-3 i|=4 on the complex plane is a x+b y-1=0 then the value of a+b is

Question

The equation of the radical axis of the two circles represented by the equations |z-2|=3 and |z-2-3 i|=4 on the complex plane is a x+b y-1=0 then the value of a+b is (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

(x-2)2+y2=9 (x-2)2+(y-3)2=16 text where z=x+i y Equation of radical axis is S-S=0 ⇒ 3 y-1=0

Q. The equation of the radical axis of the two circles represented by the equations $∣ z - 2∣ = 3$ and $∣ z - 2 - 3 i ∣ = 4$ on the complex plane is $a x + b y - 1 = 0$ then the value of $a + b$ is

$(x - 2)^{2} + y^{2} = 9$
$(x - 2)^{2} + (y - 3)^{2} = 16 where z = x + i y$
Equation of radical axis is $S - S = 0 \Rightarrow 3 y - 1 = 0$

Q. The equation of the radical axis of the two circles represented by the equations ∣z−2∣=3 and ∣z−2−3i∣=4 on the complex plane is ax+by−1=0 then the value of a+b is

(x−2)2+y2=9 (x−2)2+(y−3)2=16 where z=x+iy Equation of radical axis is S−S=0⇒3y−1=0

Q. The equation of the radical axis of the two circles represented by the equations $∣ z - 2∣ = 3$ and $∣ z - 2 - 3 i ∣ = 4$ on the complex plane is $a x + b y - 1 = 0$ then the value of $a + b$ is

$(x - 2)^{2} + y^{2} = 9$
$(x - 2)^{2} + (y - 3)^{2} = 16 where z = x + i y$
Equation of radical axis is $S - S = 0 \Rightarrow 3 y - 1 = 0$