The equation of the polar of the point (2,-1) with respect to the circle x2+y2-3 x+4 y-8=0, is

Question

The equation of the polar of the point (2,-1) with respect to the circle x2+y2-3 x+4 y-8=0, is (A) x+2 y-26=0 (B) x-2 y-26=0 (C) x+2 y+26=0 (D) None

Tardigrade Admin · Accepted Answer

Given circle is x2+y2-3 x+4 y-8=0...(i) Given point is (2,-1) let P =(2,-1). Now equation of the polar of point P with respect to circle (i) x .2+y(-1)-3((x+2/2))+4((y-1/2))-8=0 or 4 x-2 y-3 x-6+4 y-4-16=0 or x+2 y -26=0

Q. The equation of the polar of the point $(2, - 1)$ with respect to the circle $x^{2} + y^{2} - 3 x + 4 y - 8 = 0$ , is

$x + 2 y - 26 = 0$

$x - 2 y - 26 = 0$

$x + 2 y + 26 = 0$

None

Q. The equation of the polar of the point (2,−1) with respect to the circle x2+y2−3x+4y−8=0, is

x+2y−26=0

x−2y−26=0

x+2y+26=0

None

Given circle is x2+y2−3x+4y−8=0...(i) Given point is (2,−1) let P=(2,−1). Now equation of the polar of point P with respect to circle (i) x.2+y(−1)−3(2x+2​)+4(2y−1​)−8=0 or 4x−2y−3x−6+4y−4−16=0 or x+2y−26=0

Q. The equation of the polar of the point $(2, - 1)$ with respect to the circle $x^{2} + y^{2} - 3 x + 4 y - 8 = 0$ , is

$x + 2 y - 26 = 0$

$x - 2 y - 26 = 0$

$x + 2 y + 26 = 0$