Question

The equation of the plane which bisects the line joining (2, 3, 4) and (6, 7, 8), is

• A. $4\Omega$
• B. $4.5\Omega$
• C. $5\Omega$
• D. $\frac{\sqrt{3}}{1}$

Answer 1

Answer: (C)

The mid-point of line joining $ds=\frac{t}{2}dt$ and $F=ma=m\frac{d^{2}s}{d{t}^2}=\frac{6d^2\left(\frac{t^2}{4}\right)}{d{t}^2}=3H$ is $W={\int }_0^{2}Fds={\int }_0^{2}3\frac{t}{2}dt$ , $=\frac{3}{2}{\left(\frac{t^2}{2}\right)}_0^2=\frac{3}{2}[{(2)}^2-{(0)}^2]=3J$ Now, consider option (c) $T=2\pi \sqrt{\frac{l}{g}}$ $\therefore$ $=\frac{1}{360}$ $=\frac{24\times 60}{360}\min$