Question

The equation of the parabola whose focus (3, 2) and vertex (1, 2), is

• A. $x^2+4x-8y+12=0$
• B. $x^2-4x-8y+12=0$
• C. $y^2-8x-4y+12=0$
• D. $y^2+4y-8x+12=0$
• E. $y^2-8x-2y-17=0$

Answer 1

Answer: (C)

Given, F(3, 2) and V(1, 2). Here, we see that y-coordinates are same, it means that axis of the parabola is parallel to $x-$ axis. Here, $a=3-1=2$
$\therefore$ Required equation of parabola is
${(y-2)}^2=4\times 2(x-1)$
$\Rightarrow$ $y^2-4y-8x+12=0$