We have, to find the locus of the point (h,k) whose image on the line 2x−y−1=0 lies on the line y=x.
Now, the image of (h,k) on the line 2x−y−1=0 is given by 2x2−h=−1y2−k=−52(2h−k−1)
or x2=5−3h+4k+4
and y2=54h+3k−2
The point lies on y=x. Then, 5−3h+4k+4=54h+3k−2
or 7h−k=6