Question

The equation of the line joining the points $(-3,4,11)$ and $(1,-2,7)$ is

• A. $\frac{x+3}{2}=\frac{y-4}{3}=\frac{z-11}{4}$
• B. $\frac{x+3}{-2}=\frac{y-4}{3}=\frac{z-11}{2}$
• C. $\frac{x+3}{-2}=\frac{y+4}{3}=\frac{z+11}{4}$
• D. $\frac{x+3}{-2}=\frac{y+4}{-3}=\frac{z+11}{2}$

Answer 1

Answer: (B)

$D.r^{\prime }.s$ of the line joining the given points are
$(1-(-3)$, $2-4$, $7-11)$
i.e., $(4,-6,-4)$ or $(-2,3,2)$
$\therefore$ Equation of line is $\frac{x+3}{-2}=\frac{y-4}{3}=\frac{z-11}{2}$