The equation of the hypotenuse of a right isosceles triangle ABC is x-2 y-3=0. If the vertex of the right angle lie at the point C (1,6) then:

Question

The equation of the hypotenuse of a right isosceles triangle ABC is x-2 y-3=0. If the vertex of the right angle lie at the point C (1,6) then: (A) area of the triangle ABC is less than 40 sq. units (B) area of the triangle ABC is more than 30 sq. units (C) the equation of the two legs of the triangle ABC are 3 x - y +3=0 and x +3 y -19=0 (D) circumradius of the triangle ABC is (14 √5/5)

Tardigrade Admin · Accepted Answer

area of right isosceles triangle is p 2=(196/5)

Q. The equation of the hypotenuse of a right isosceles triangle $A BC$ is $x - 2 y - 3 = 0$ . If the vertex of the right angle lie at the point $C (1, 6)$ then:

area of the $△ A BC$ is less than $40 s q$ . units

area of the $△ A BC$ is more than $30 s q$ . units

the equation of the two legs of the $△ A BC$ are $3 x - y + 3 = 0$ and $x + 3 y - 19 = 0$

circumradius of the $△ A BC$ is $\frac{14 5}{5}$

area of right isosceles triangle is $p^{2} = \frac{196}{5}$

Q. The equation of the hypotenuse of a right isosceles triangle ABC is x−2y−3=0. If the vertex of the right angle lie at the point C(1,6) then:

area of the △ABC is less than 40sq. units

area of the △ABC is more than 30sq. units

the equation of the two legs of the △ABC are 3x−y+3=0 and x+3y−19=0

circumradius of the △ABC is 5145​​