The equation of the bisectors of the angles between the lines represented by the equation 2(x + 2)2+3(x + 2)(y - 2)-2(y - 2)2=0 is

Question

The equation of the bisectors of the angles between the lines represented by the equation 2(x + 2)2+3(x + 2)(y - 2)-2(y - 2)2=0 is (A) 3x2-8xy-3y2-28x+4y+32=0 (B) 3x2+8xy-3y2+28x-4y+32=0 (C) 3x2-8xy-3y2+28x-4y+32=0 (D) 3x2-8xy-3y2+28x-4y-32=0

Tardigrade Admin · Accepted Answer

Equation of the bisectors would be ((x + 2)2 - (y - 2)2/2 - (- 2))=((x + 2) (. y - 2 .)/(3)2) 3[x2 + 4 x + 4 - y2 + 4 y - 4]=8 [x y - 2 x + 2 y - 4] 3x2+12x-3y2+12y=8xy-16x+16y-32 3x2-8xy-3y2+28x-4y+32=0

Q. The equation of the bisectors of the angles between the lines represented by the equation $2 (x + 2)^{2} + 3 (x + 2) (y - 2) - 2 (y - 2)^{2} = 0$ is

$3 x^{2} - 8 x y - 3 y^{2} - 28 x + 4 y + 32 = 0$

$3 x^{2} + 8 x y - 3 y^{2} + 28 x - 4 y + 32 = 0$

$3 x^{2} - 8 x y - 3 y^{2} + 28 x - 4 y + 32 = 0$

$3 x^{2} - 8 x y - 3 y^{2} + 28 x - 4 y - 32 = 0$

Q. The equation of the bisectors of the angles between the lines represented by the equation 2(x+2)2+3(x+2)(y−2)−2(y−2)2=0 is

3x2−8xy−3y2−28x+4y+32=0

3x2+8xy−3y2+28x−4y+32=0

3x2−8xy−3y2+28x−4y+32=0

3x2−8xy−3y2+28x−4y−32=0

Equation of the bisectors would be 2−(−2)(x+2)2−(y−2)2​=23​(x+2)(y−2)​ 3[x2+4x+4−y2+4y−4]=8[xy−2x+2y−4] 3x2+12x−3y2+12y=8xy−16x+16y−32 3x2−8xy−3y2+28x−4y+32=0

Q. The equation of the bisectors of the angles between the lines represented by the equation $2 (x + 2)^{2} + 3 (x + 2) (y - 2) - 2 (y - 2)^{2} = 0$ is

$3 x^{2} - 8 x y - 3 y^{2} - 28 x + 4 y + 32 = 0$

$3 x^{2} + 8 x y - 3 y^{2} + 28 x - 4 y + 32 = 0$

$3 x^{2} - 8 x y - 3 y^{2} + 28 x - 4 y + 32 = 0$

$3 x^{2} - 8 x y - 3 y^{2} + 28 x - 4 y - 32 = 0$