The equation of line passing through point (1,2) and making up angle 30° with Y-axis is

Question

The equation of line passing through point (1,2) and making up angle 30° with Y-axis is (A) y+√3 x-2+√3=0 (B) y-√3 x-2+√3=0 (C) y+√3 x+2-√3=0 (D) y+√3 x-2-√3=0

Tardigrade Admin · Accepted Answer

Line makes 60° with x-axis ⇒ m= tan 60°=√3 ∴ equation y-2=√3(x-1) ⇒ y-√3 x-2+√3=0

Q. The equation of line passing through point $(1, 2)$ and making up angle $3 0^{\circ}$ with $Y$ -axis is

$y + 3 x - 2 + 3 = 0$

$y - 3 x - 2 + 3 = 0$

$y + 3 x + 2 - 3 = 0$

$y + 3 x - 2 - 3 = 0$

Line makes $6 0^{\circ}$ with $x$ -axis
$\Rightarrow m = tan 6 0^{\circ} = 3$
$∴$ equation $y - 2 = 3 (x - 1)$
$\Rightarrow y - 3 x - 2 + 3 = 0$

Q. The equation of line passing through point (1,2) and making up angle 30∘ with Y-axis is

y+3​x−2+3​=0

y−3​x−2+3​=0

y+3​x+2−3​=0

y+3​x−2−3​=0