The equation of common normal to the circle x2+y2-12 x+16=0 and parabola y2=4 x is

Question

The equation of common normal to the circle x2+y2-12 x+16=0 and parabola y2=4 x is (A) y=0 (B) 2 x-y=12 (C) 2 x+y=12 (D) All of the above

Tardigrade Admin · Accepted Answer

y=m x-2 a m-a m3 y=m x-2 m-m3 Passes through centre of circle =6 m-2 m-m3 ⇒ 4 m-m3=0 ⇒ m=0, m=2, m=-2

Q. The equation of common normal to the circle $x^{2} + y^{2} - 12 x + 16 = 0$ and parabola $y^{2} = 4 x$ is